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Searching for more than one of anything

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#1 joshia

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Posted 07 January 2013 - 06:12 AM

Is it possible to use the searchbar to find all verses containing at least to of something

(fx containing at least to infinitives)

 

this construct gets things done:

Screen Shot 2013-01-07 at 12.07.09 PM.png

 

But can I do something like this

[COUNT >1]@[VERB infinitive]

 

I know count dosn't work this way - but you get the point.

 

Blessings

    Erik

 


#2 Joel Brown

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Posted 07 January 2013 - 06:22 AM

Erik, it sorta depends on what you are looking for.  Your construct search is looking for two VERB infinitives within the same verse, which can easily be done in the search box:

 

[VERB infinitive] <FOLLOWED BY> [VERB infinitive]

 

Now, if you want them to agree on a variety of things (lemma, inflected form, root, etc.), you'll have to use a construct, as the AGREE bubble practically only exists within the construct.  This would look like this:Screen shot 2013-01-07 at 1.19.42 PM.png

 

Finally, your search [COUNT >1}@[VERB infinitive] is actually pretty close.  You can do [COUNT 2-100000]@[VERB infinitive] to find infinitive Verbs that occur more than once within your search range.  But, this also might not be what you are looking for.  My guess is what you want is the construct AGREE search, which due to its nature, can only really be built in the construct.

 

Edit: Fixed search logic, as [VERB] <AND> [VERB] will also find hits that only have 1 VERB.


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#3 joshia

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Posted 07 January 2013 - 06:53 AM

Hi Joel!

Thanks for the reply.

Trying to keep it simple, as I'm helping teaching a bunch of students, the course is planned for bibleworks, but I'm teaching the accordance users.

But since I'm looking for verses that contain at least to infinitives, at not what infinitives are present more than once in the search-range option 3 is invalid.

So I will teach them the [followed by] methond, and the more advanced construct.

 






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